Wireless 101
M06 · L03
Module 6 · Lesson 3

Bits per Hertz

Spectrum is the one thing you cannot manufacture — it is licensed and auctioned for billions. So the number that matters is not raw rate but rate per hertz.

01 / 11
Wireless 101
M06 · L03
The definition

Spectral Efficiency

Bits / second / hertz
\eta = \frac{R_b}{B}

A link at 2 b/s/Hz gives 40 Mbps in a 20 MHz channel — or 2 Gbps in a gigahertz. One number, comparable across every system ever built.

02 / 11
Wireless 101
M06 · L03
From our own choices

Three Levers

Practical η
\eta = \frac{R_c \, \log_2 M}{1 + \alpha}

Modulation order (log₂M), code rate Rc, and roll-off α. Denser modulation, lighter coding, tighter shaping — each buys η and each costs SNR.

03 / 11
Wireless 101
M06 · L03
Worked values

Putting Numbers On It

Uncoded, with α = 0.25: QPSK gives 2/1.25 = 1.6. At α = 0.1, 64-QAM gives 6/1.1 = 5.45 — and a 3/4 code drops that to 4.09.

QPSK
1.6
64-QAM
5.45
256-QAM
7.27
04 / 11
Wireless 101
M06 · L03
Shannon, restated

The Ceiling on η

Shannon bound
\eta \le \log_2\!\left(1 + \mathrm{SNR}\right)

Divide capacity by B and the ceiling depends on SNR alone: 3.46 b/s/Hz at 10 dB, 6.66 at 20 dB. Roughly one more b/s/Hz per 3 dB.

05 / 11
Wireless 101
M06 · L03
Try it

Mind the Gap

The curve is Shannon’s ceiling; the bars are real schemes. Slide the SNR and see which ones the channel can actually support — and how much headroom is left.

SNR 18 dB · max 6.0
06 / 11
Wireless 101
M06 · L03
Out in the world

A Century of Progress

  • AM broadcast — ~0.5 b/s/Hz, analog
  • GSM (2G) — ~0.17 b/s/Hz
  • LTE 2×2 MIMO — ~7.5 b/s/Hz peak
  • WiFi 6 — ~8 b/s/Hz per stream (1024-QAM)
  • 5G massive MIMO — 30+ b/s/Hz per cell
07 / 11
Wireless 101
M06 · L03
Not a Shannon violation

How 5G Gets 30+

Those figures come from spatial multiplexing: MIMO opens several parallel channels in the same band, and each obeys Shannon separately. The bound applies per channel — MIMO multiplies the channels.

08 / 11
Wireless 101
M06 · L03
The fine print

Overheads Nobody Advertises

No real link delivers its theoretical η. The cyclic prefix (~7% of every OFDM symbol), guard subcarriers, pilot tones, and control headers together take 20–30% off the top. Also: always ask whether a quoted figure is peak or average.

09 / 11
Wireless 101
Knowledge Check

Check what stuck

Four questions from this lesson. Answer to see why — the explanation appears whether you were right or wrong. Nothing is scored or saved.

Question 1 of 0
Score 0/0

10 / 11
Wireless 101
M06 · L03
Recap

What you learned

  • η = Rb/B in b/s/Hz — the yardstick, because spectrum is finite
  • η = Rc·log₂M/(1+α): modulation, coding, and roll-off
  • Ceiling η ≤ log₂(1+SNR) — about +1 b/s/Hz per 3 dB
  • MIMO multiplies channels; overheads cost 20–30%; peak ≠ average
Up next in Module 6
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