Wireless 101
M09 · L03
Module 9 · Lesson 3

The Noise Floor Was Never the Problem

M9-L2 warned you about a BER curve that flattens and stops responding to power. Here is why: in almost every deployed system the limit is not thermal noise but other transmitters.

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Wireless 101
M09 · L03
One worked case

Twenty-One dB Becomes Nine

S = −80 dBm, thermal N = −101 dBm, a co-channel cell at I = −90 dBm. Convert and add: 1.000×10−9 + 0.0794×10−9 = 1.0794×10−9 mW = −89.67 dBm.

SNR only
21 dB
SINR
9.67 dB
Noise adds
0.33 dB

The noise term is a rounding error once interference sits 11 dB above it. Shaving a decibel off the noise figure buys you nothing here.

02 / 11
Wireless 101
M09 · L03
The 0.30 dB that built cellular

Power Helps Nobody

Signal to interference plus noise ratio
\mathrm{SINR} = \frac{S}{I+N}

Turn every transmitter up by 10 dB: S = −70, I = −80, N unchanged. SINR goes 9.67 → 9.97 dB. Ten decibels bought 0.30 dB, because everyone rose together.

03 / 11
Wireless 101
M09 · L03
Co-channel interference

No Filter Can Save You

CCI is on your own frequency, so there is no frequency difference to filter. Cellular fixes it geometrically: split channels into N groups and space the repeats by D/R = √(3N).

N = 3
3.00
N = 7
4.58
N = 12
6.00

Only certain N tile a hexagonal plane — 1, 3, 4, 7, 9, 12, 13 — which is why you never meet a reuse factor of 5.

04 / 11
Wireless 101
M09 · L03
Six first-tier interferers

Where 18 dB Came From

Hexagonal C over I estimate
\frac{C}{I} \approx \frac{(D/R)^{n}}{6} = \frac{(3N)^{n/2}}{6}
  • N = 7, n = 4: 21² = 441, /6 = 73.5 → 18.66 dB
  • N = 12: 1296/6 = 216 → 23.34 dB
  • Cost of that 4.68 dB: 48 channels per cell → 28, a 42% cut
  • At n = 3, nothing in the table reaches 18 dB
05 / 11
Wireless 101
M09 · L03
Try it — S fixed at −80 dBm

SINR and Reuse Explorer

Move I past N and watch the weaker term stop mattering. The lower panel is C/I against reuse factor at your exponent.

I dBm −90 dBm
N dBm −101 dBm
exp n n = 4.0
I+N 1.079e−9 mW SINR 9.67 dB SNR 21.0 dB N=7: 18.66 dB interference-limited
06 / 11
Wireless 101
M09 · L03
Adjacent channel interference

A Ratio Problem, Not a Leak

An ACLR of 45 dBc puts the leakage 45 dB below its own carrier. Arriving 30 dB stronger than your wanted signal, that leakage lands 45 − 30 = 15 dB below it. Harmless.

  • Same transmitter, 50 dB stronger: leakage +5 dB above — link dead
  • 500 m vs 20 m at n = 3.5: 35 log₁₀25 = 48.93 dB imbalance
  • So the leakage sits 3.93 dB above what you wanted
  • The near-far problem is a power-control problem
07 / 11
Wireless 101
M09 · L03
Interference from your own past

Five Symbols Deep

When delay spread causes ISI
\sigma_\tau < 0.1\,T_s = \frac{0.1}{R_s}

Urban στ = 1 µs (M8-L3) at 5 MBd gives Ts = 200 ns, so the spread covers 5 symbols. ISI is made of your own signal, so more power moves it not at all.

08 / 11
Wireless 101
M09 · L03
The caveat about M9-L2

Impulses Are Not Gaussian

  • Noise σ for 99% of the time, 10σ for 1%
  • Q(4) predicts 3.17×10−5; the truth is 3.48×10−3
  • 110× worse, while average noise power rose only 2.99 dB
  • Buying it back with power would take 16.7 dB
  • Ovens at 2.45 GHz, LED drivers, power lines, IP3 products

Averaged noise power is the wrong statistic, and so is the independent-bit assumption behind PER.

09 / 11
Wireless 101
Knowledge Check

Check what stuck

Four questions from this lesson. Answer to see why — the explanation appears whether you were right or wrong. Nothing is scored or saved.

Question 1 of 0
Score 0/0

10 / 11
Wireless 101
M09 · L03
Recap

What you learned

  • SINR = S/(I+N); add powers, never decibels
  • I ≫ N makes transmit power worth 0.30 dB
  • D/R = √(3N); N = 7 at n = 4 gives 18.66 dB
  • ACI is a power ratio; ISI is your own signal
  • Filtering cannot touch CCI — geometry and control can
Up next in Module 9
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